A) \[C{{O}_{2}}\]
B) \[1\times {{10}^{-10}}\]
C) \[1.435\times {{10}^{-5}}\]
D) \[108\times {{10}^{-3}}\]
Correct Answer: B
Solution :
\[S=1.435\times {{10}^{-3}}\,g/l\],\[=\frac{1.435\times {{10}^{-3}}}{143.5}={{10}^{-5}}\]M \[{{K}_{sp}}=S\times S={{10}^{-10}}\]You need to login to perform this action.
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