JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Critical Thinking

  • question_answer
    In the figure is shown Young?s double slit experiment. Q is the position of the first bright fringe on the right side of O. P is the 11th fringe on the other side, as measured from Q. If the wavelength of the light used is \[6000\times {{10}^{-10}}m\], then \[{{S}_{1}}B\] will be equal to                                                                          [CPMT 1986, 92]

    A)            \[6\times {{10}^{-6}}m\]

    B)            \[6.6\times {{10}^{-6}}m\]

    C)            \[3.138\times {{10}^{-7}}m\]

    D)            \[3.144\times {{10}^{-7}}m\]

    Correct Answer: A

    Solution :

               P is the position of 11th bright fringe from Q. From central position O, P will be the position of 10th bright fringe. Path difference between the waves reaching at P = S1B =10 l = 10 ´ 6000 ´ 10?10 = 6 ´ 10?6m.


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