A) \[3{{a}^{2}}+10ab+3{{b}^{2}}=0\]
B) \[3{{a}^{2}}+2ab+3{{b}^{2}}=0\]
C) \[3{{a}^{2}}-10ab+3{{b}^{2}}=0\]
D) \[3{{a}^{2}}-2ab+3{{b}^{2}}=0\]
Correct Answer: B
Solution :
Angle between the given lines is \[\tan \frac{\pi }{4}=\frac{2\sqrt{{{(a+b)}^{2}}-ab}}{a+b}\] Þ \[\frac{2\sqrt{{{(a+b)}^{2}}-ab}}{a+b}=1\] Þ \[3{{a}^{2}}+2ab+3{{b}^{2}}=0\]You need to login to perform this action.
You will be redirected in
3 sec