A) \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\]
B) \[{{(N{{H}_{4}})}_{2}}(TiC{{l}_{6}})\]
C) \[VOS{{O}_{4}}\]
D) \[{{K}_{3}}\left[ Cu(C{{N}_{4}}) \right]\]
Correct Answer: C
Solution :
\[{{V}^{+4}}\,\to \,\,3{{d}^{1}}4{{s}^{0}}\] 1 unpaired electrons. Hence, it is paramagnetic and coloured compound.
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