A) A.M.
B) G.M.
C) H.M.
D) None of these
Correct Answer: C
Solution :
Let, the distance of school from home = d and time taken are \[{{t}_{1}}\]and t2. \[\therefore {{t}_{1}}=\frac{d}{x}\] and \[{{t}_{2}}=\frac{d}{y}\] Avg. velocity =\[\frac{\text{Total}\,\text{dis}\text{tance}}{\text{Total}\,\text{time}}\] \[=\frac{2d}{\left( \frac{d}{x}+\frac{d}{y} \right)}=\frac{2xy}{x+y}\], which is the H.M. of x and y.
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