A) 30°
B) 60°
C) 90°
D) 120°
Correct Answer: D
Solution :
\[y=a\sin (\omega t+{{\varphi }_{0}})\]. According to the question \[y=\frac{a}{2}\]\[\Rightarrow \]\[\frac{a}{2}=a\sin (\omega \,t+{{\varphi }_{0}})\]\[\Rightarrow (\omega \,t+{{\varphi }_{0}})=\varphi =\frac{\pi }{6}\]or \[\frac{5\pi }{6}\] Physical meaning of \[\varphi =\frac{\pi }{6}\] : Particle is at point P and it is going towards B Physical meaning of \[\varphi =\frac{5\pi }{6}\] : Particle is at point P and it is going towards O So phase difference \[\Delta \varphi =\frac{5\pi }{6}-\frac{\pi }{6}=\frac{2\pi }{3}=120{}^\circ \]You need to login to perform this action.
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