A) \[\frac{1}{u}\text{ versus }\frac{1}{v}\]
B) m versus u
C) u versus v
D) m versus v
Correct Answer: A
Solution :
For a lens \[\frac{1}{f}=\frac{1}{v}-\frac{1}{u}\]\[\Rightarrow \frac{1}{v}=\frac{1}{u}+\frac{1}{f}\] .....(i) Also \[m=\frac{f-v}{f}=1-\frac{v}{f}\]\[\Rightarrow m=\left( -\frac{1}{f} \right)\ v+1\] ....(ii) On comparing equations (i) and (ii) with \[y=mx+c.\] It is clear that relationship between \[\frac{1}{v}\] vs \[\frac{1}{u}\] and m vs v is linear.
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