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JEE Main & Advanced Physics Wave Mechanics Question Bank Critical Thinking

  • question_answer
    41 forks are so arranged that each produces 5 beats per sec when sounded with its near fork. If the frequency of last fork is double the frequency of first fork, then the frequencies of the first and last fork are respectively                                                                         [MP PET 1997; KCET 2002]

    A)            200, 400                                  

    B)            205, 410

    C)            195, 390                                  

    D)            100, 200

    Correct Answer: A

    Solution :

                       Similar to previous question                    nFirst = nFirst + (N ? 1)x   2n = n      + (41 ? 1) ´ 5 Þ nFirst = 200 Hz and nLast = 400 Hz


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