A) 12
B) 7
C) 18
D) 4
Correct Answer: B
Solution :
For maximum intensity on the screen \[d\sin \theta =n\lambda \Rightarrow \sin \theta =\frac{n\lambda }{d}=\frac{n(2000)}{7000}=\frac{n}{3.5}\] Since maximum value of \[\sin \theta \] is 1 So \[n=0,\,\,1,\,\,2,\,\,3,\] only. Thus only seven maximas can be obtained on both sides of the screen.
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