• # question_answer The area bounded by the angle bisectors of the lines ${{x}^{2}}-{{y}^{2}}+2y=1$ and the line $x+y=3$, is [IIT Screening 2004] A)            2     B)            3 C)            4     D)            6

The angle bisectors of the lines given by ${{x}^{2}}-{{y}^{2}}+2y=1$ are $x=0$, $y=1$.            Therefore, required area                                 = $\frac{1}{2}\times 2\times 2=2$.