A) \[T{{i}^{3+}}\]
B) \[T{{i}^{4+}}\]
C) \[C{{a}^{2+}}\]
D) \[S{{c}^{+}}\]
Correct Answer: A
Solution :
\[(Ar)\,\,3{{s}^{1}}+3=Ti\], it means \[{{M}^{3+}}\] form \[T{{i}^{3+}}\] ion.
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