A) \[<8abc\]
B) \[>8abc\]
C) \[=8abc\]
D) None of these
Correct Answer: B
Solution :
Since A.M. > G.M., we have \[\frac{a+b}{2}>\sqrt{ab},\ \frac{b+c}{2}>\sqrt{bc}\] and \[\frac{a+c}{2}>\sqrt{ac}\]. Multiplying these inequalities, we get \[(a+b)(b+c)(c+a)>8abc\].
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