A) Zero
B) 4 volts (VP > VQ)
C) 4 volts (VQ > VP)
D) 2.5 volts (VQ > VP)
Correct Answer: D
Solution :
\[{{R}_{eq}}=\frac{5}{2}\Omega \] \[i=\frac{20}{\frac{5}{2}+1.5}=5A\] Potential difference between X and P, \[{{V}_{X}}-{{V}_{P}}=\left( \frac{5}{2} \right)\times 3=7.5V\] ....(i) \[{{V}_{X}}-{{V}_{Q}}=\frac{5}{2}\times 2=5V\] ?(ii) On solving (i) and (ii) \[{{V}_{P}}-{{V}_{Q}}=-2.5\text{ }volt\text{; }{{V}_{Q}}>{{V}_{P}}\]. Short Trick : \[({{V}_{P}}-{{V}_{Q}})=\frac{i}{2}({{R}_{2}}-{{R}_{1}})\]\[=\frac{5}{2}(2-3)=-\,2.5\] Þ \[{{V}_{Q}}>{{V}_{P}}\]You need to login to perform this action.
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