A) \[{{T}_{2}}\] was decreased
B) \[{{T}_{2}}\] was increased
C) \[{{T}_{1}}\] was increased
D) \[{{T}_{1}}\] was kept constant
Correct Answer: B
Solution :
Using \[n=\frac{1}{2l}\sqrt{\frac{T}{m}}\]; As \[{{T}_{1}}>{{T}_{2}}\]Þ \[{{n}_{1}}>{{n}_{2}}\] giving \[{{n}_{1}}-{{n}_{2}}=6\] The beat frequency of 6 will remain fixed when (i) \[{{n}_{1}}\] remains same but \[{{n}_{2}}\] is increased to a new value \[({{n}_{2}}^{\prime }-{{n}_{2}}=12)\] by increasing tension \[{{T}_{2}}\]. (ii) n2 remains same but n1 is decreased to a new value \[({{n}_{1}}-{{n}_{1}}'=12)\] by decreasing tension T1.
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