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JEE Main & Advanced Physics Semiconducting Devices Question Bank Critical Thinking

  • question_answer
      For the transistor circuit shown below, if b = 100, voltage drop between emitter and base is 0.7 V then value of VCE will be

    A)            10 V

    B)            5 V

    C)            13 V 

    D)            0 V

    Correct Answer: C

    Solution :

                       \[{{i}_{b}}=\frac{5-0.7}{8.6}=0.5\,mA\] Þ \[{{I}_{c}}=\beta \,{{I}_{b}}=100\times 0.5\,mA\] By using \[{{V}_{CE}}={{V}_{CC}}-{{I}_{c}}{{R}_{L}}=18-50\times {{10}^{-3}}\times 100=13V\]


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