A) 0
B) \[\frac{-24}{5}\]
C) \[\frac{24}{5}\]
D) \[\frac{48}{5}\]
Correct Answer: A
Solution :
\[3\tan A-4=0\Rightarrow \tan A=\frac{4}{3}\Rightarrow \sin A=-\frac{4}{5},\cos A=-\frac{3}{5}\] \[\therefore \] \[5\sin 2A+3\sin A+4\cos A\] = \[10\sin A\cos A+3\sin A+4\cos A\] = \[10\,\left( \frac{12}{25} \right)-\frac{12}{5}-\frac{12}{5}=0\].
You need to login to perform this action.
You will be redirected in
3 sec
