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JEE Main & Advanced Chemistry Coordination Chemistry Question Bank Critical Thinking Coordination

  • question_answer
    Mixture \[X=0.02\,mol\] of \[[Co{{(N{{H}_{3}})}_{5}}S{{O}_{4}}]\,Br\] and 0.02 mol of \[[Co{{(N{{H}_{3}})}_{5}}Br]S{{O}_{4}}\] was prepared in 2 litre of solution 1 litre of mixture X + excess \[AgN{{O}_{3}}\to Y\]. 1 litre of mixture X + excess \[BaC{{l}_{2}}\to Z\] Number of moles of Y and Z are [IIT JEE 2003]

    A) 0.01, 0.01

    B) 0.02, 0.01

    C) 0.01, 0.02

    D) 0.02, 0.02

    Correct Answer: A

    Solution :

    \[\underset{0.02\,\text{mole}}{\mathop{[Co\,{{(N{{H}_{3}})}_{5}}S{{O}_{4}}]\,Br}}\,+AgN{{O}_{3}}\to \]\[\underset{0.02\,\text{mole }(y)}{\mathop{[Co\,{{(N{{H}_{3}})}_{5}}.\,S{{O}_{4}}]\,N{{O}_{3}}}}\,+AgBr\] \[\underset{0.02\,\text{mole}}{\mathop{[Co\,{{(N{{H}_{3}})}_{5}}B{{r}_{2}}]S{{O}_{4}}}}\,+BaC{{l}_{2}}\to \]\[\underset{0.02\,\text{mole}\,(z)}{\mathop{[Co\,{{(N{{H}_{3}})}_{5}}Br]\,C{{l}_{2}}}}\,+BaS{{O}_{4}}\] On using one lit. Solution, we will get 0.01 mole y and 0.01 mole z.


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