JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Critical Thinking

  • question_answer
    Two coherent sources separated by distance\[d\]are radiating in phase having wavelengthl. A detector moves in a big circle around the  two sources in the plane of the two sources. The angular position of n = 4 interference maxima is given as

    A)            \[{{\sin }^{-1}}\frac{n\lambda }{d}\]

    B)            \[{{\cos }^{-1}}\frac{4\lambda }{d}\]

    C)            \[{{\tan }^{-1}}\frac{d}{4\lambda }\]

    D)            \[{{\cos }^{-1}}\frac{\lambda }{4d}\]

    Correct Answer: B

    Solution :

               Here path difference at a point \[P\] on the circle is given by \[\Delta x=d\cos \theta \]          ?.. (i) For maxima at \[P\] \[\Delta x=n\lambda \]                ?.. (ii) From equation (i) and (ii) \[n\lambda =d\cos \theta \Rightarrow \theta {{\cos }^{-1}}\left( \frac{n\lambda }{d} \right)={{\cos }^{-1}}\left( \frac{4\lambda }{d} \right)\]


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