11th Class Mathematics Other Series Question Bank Critical Thinking

  • question_answer The A.M., H.M. and G.M. between two numbers are \[\frac{144}{15}\], 15 and 12, but not necessarily in this order. Then H.M., G.M. and A.M. respectively are

    A) \[15,\ 12,\ \frac{144}{15}\]

    B) \[\frac{144}{15},\ 12,\ 15\]

    C) \[12,\ 15,\ \frac{144}{15}\]

    D) \[\frac{144}{15},\ 15,\ 12\]

    Correct Answer: B

    Solution :

    As we know \[A.M.>G.M.>H.M.\] \[\therefore \]\[A.M.=15,\ G.M.=12,\ H.M.=\frac{144}{15}\].


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