A) \[n=3,\] \[{{f}_{2}}=\frac{3}{4}{{f}_{1}}\]
B) \[n=3,\] \[{{f}_{2}}=\frac{5}{4}{{f}_{1}}\]
C) \[n=5,\] \[{{f}_{2}}=\frac{5}{4}{{f}_{1}}\]
D) \[n=5,\] \[{{f}_{2}}=\frac{3}{4}{{f}_{1}}\]
Correct Answer: C
Solution :
Open pipe resonance frequency \[{{f}_{1}}=\frac{2v}{2L}\] Closed pipe resonance frequency \[{{f}_{2}}=\frac{nv}{4L}\] \[{{f}_{2}}=\frac{n}{4}{{f}_{1}}\] (where n is odd and \[{{f}_{2}}>{{f}_{1}}\]) \ n = 5
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