JEE Main & Advanced Physics Ray Optics Question Bank Critical Thinking

  • question_answer
    The average distance between the earth and moon is  \[38.6\times {{10}^{4}}\]km. The minimum separation between the two points on the surface of the moon that can be resolved by a telescope whose objective lens has a diameter of 5 m with \[\lambda =6000\ {AA}\] is                                                              [MP PMT 1993]

    A) 5.65 m                                     

    B) 28.25 m 

    C) 11.30 m                                  

    D) 56.51 m

    Correct Answer: D

    Solution :

                       Resolving power \[=\frac{1.22\ \lambda }{a}=\frac{1.22\times 6000\times {{10}^{-10}}}{5}\] Also resolving power \[=\frac{d}{D}=\frac{d}{38.6\times {{10}^{7}}}\]                    \[\therefore \frac{1.22\times 6\times {{10}^{-7}}}{5}=\frac{d}{38.6\times {{10}^{7}}}\]            Þ\[d=\frac{1.22\times 6\times {{10}^{-7}}\times 38.6\times {{10}^{7}}}{5}m=56.51\ m\]


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