A) \[\frac{R}{2}\]
B) \[\frac{R}{\sqrt{2}}\]
C) R
D) \[\sqrt{2}R\]
Correct Answer: B
Solution :
\[{{I}_{edge}}=\frac{L\cos \theta }{({{h}^{2}}+{{r}^{2}})}=\frac{Lh}{{{({{h}^{2}}+{{r}^{2}})}^{3/2}}}\] For maximum extensity \[\frac{dI}{dh}=0\] Applying this condition have get \[h=\frac{r}{\sqrt{2}}\]
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