A) \[C{{H}_{3}}N{{H}_{2}}\]
B) \[R{{O}^{-}}\]
C) \[AlC{{l}_{3}}\]
D) \[C{{H}_{3}}MgBr\]
Correct Answer: A
Solution :
\[C{{H}_{3}}\overset{\cdot \ \cdot }{\mathop{N}}\,{{H}_{2}},\ R-\underset{\cdot \ \cdot }{\overset{\cdot \ \cdot \ }{\mathop{O}}}\,\,-,\ C{{H}_{3}}-Mg-\underset{\cdot \ \cdot }{\overset{\cdot \ \cdot }{\mathop{B}}}\,r:\] are nucleophiles due to presence of lone pairs.
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