JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Critical Thinking

  • question_answer
    Light is incident normally on a diffraction grating through which the first order diffraction is seen at 32o. The second order diffraction will be seen at

    A)            48o

    B)            64o

    C)            80o

    D)            There is no second order diffraction in this case

    Correct Answer: D

    Solution :

               For a grating \[(e+d)\sin {{\theta }_{n}}=n\lambda \] where \[(e+d)=\] grating element \[\sin {{\theta }_{n}}=\frac{n\lambda }{(e+d)}\] For \[n=1,\] \[\sin {{\theta }_{1}}=\frac{\lambda }{(e+d)}=\sin 32{}^\circ \] This is more than 0.5. Now \[\sin {{\theta }_{2}}\] will be more than \[2\times 0.5,\] which is not possible.


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