JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Critical Thinking

  • question_answer
    A uniform rod of length 2.0 m is suspended through an end and is set into oscillation with small amplitude under gravity. The time period of oscillation is approximately                                    [AMU (Med.) 2000]

    A)            1.60 sec                                  

    B)            1.80 sec

    C)            2.0 sec                                     

    D)            2.40 sec

    Correct Answer: D

    Solution :

                       This is the special case of physical pendulum and in this case \[T=2\pi \sqrt{\frac{2l}{3g}}\] \[\Rightarrow \] \[T=2\times 3.14\sqrt{\frac{2\times 2}{3\times 9.8}}=2.31\sec \approx 2.4\sec \]


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