A) 156°
B) 140°
C) 136°
D) 126°
Correct Answer: A
Solution :
Total phase difference = Initial phase difference + Phase difference due to path \[=66{}^\circ +\frac{360{}^\circ }{\lambda }\times \Delta x\]\[=66{}^\circ +\frac{360{}^\circ }{\lambda }\times \frac{\lambda }{4}\]\[=66{}^\circ +90=156{}^\circ \]
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