A) \[1.1\times {{10}^{-11}}\]
B) \[2.2\times {{10}^{-12}}\]
C) \[3.3\times {{10}^{-13}}\]
D) \[4.4\times {{10}^{-14}}\]
Correct Answer: B
Solution :
Average energy density of electric field is given by \[{{u}_{e}}=\frac{1}{2}{{\varepsilon }_{0}}{{E}^{2}}=\frac{1}{2}{{\varepsilon }_{0}}{{\left( \frac{{{E}_{0}}}{\sqrt{2}} \right)}^{2}}=\frac{1}{4}{{\varepsilon }_{0}}E_{0}^{2}\] \[=\frac{1}{4}\times 8.85\times {{10}^{-12}}{{(1)}^{2}}=2.2\times {{10}^{-12}}J/{{m}^{3}}.\]
You need to login to perform this action.
You will be redirected in
3 sec
