A) 2
B) 5
C) 7
D) 9
Correct Answer: A
Solution :
Two isomers \[C{{H}_{3}}-\underset{Cl}{\mathop{\underset{|\,\,\,\,}{\mathop{CH}}\,}}\,-C{{H}_{3}}\] and \[C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}Cl\] are possible for \[{{C}_{3}}{{H}_{7}}Cl\].
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