A) Oxidising agent
B) Reducing agent
C) Both the above
D) None of these
Correct Answer: B
Solution :
\[LiAl{{H}_{4}}\] act as reducing agent \[C{{H}_{3}}CHO+2H\xrightarrow{LiAl{{H}_{4}}}C{{H}_{3}}C{{H}_{2}}OH\]
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