A) 2050 Å
B) 2240 Å
C) 2525 Å
D) 2935 Å
Correct Answer: C
Solution :
\[\frac{hc}{\lambda }=E\] = eV \[\Rightarrow \lambda =\frac{hc}{eV}-\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{1.6\times {{10}^{-19}}\times 4.9}=2525\overset{\circ }{\mathop{A}}\,\]You need to login to perform this action.
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