JEE Main & Advanced Physics Communication System / संचार तंत्र Question Bank Critical Thinking

  • question_answer
    A transmitter supplies 9 kW to the aerial when unmodulated. The power radiated when modulated to 40% is

    A)            5 kW                                        

    B)            9.72 kW

    C)            10 kW                                      

    D)            12 kW

    Correct Answer: B

    Solution :

                       \[{{P}_{t}}={{P}_{c}}\,\left[ 1+\frac{{{m}^{2}}}{2} \right]=9\,\left[ 1+\frac{{{(0.4)}^{2}}}{2} \right]\] \[=9\,\left[ 1+\frac{0.16}{2} \right]\]    (Q m = 40% = 0.4) = 9 (1.08) = 9.72 kW


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