A) 25 Hz
B) 50 Hz
C) 100 Hz
D) 200 Hz
Correct Answer: B
Solution :
In condition of resonance, frequency of a.c. will be equal to natural frequency of wire \[n=\frac{1}{2l}\sqrt{\frac{T}{m}}=\frac{1}{2\times 1}\sqrt{\frac{10\times 9.8}{9.8\times {{10}^{-3}}}}=\frac{100}{2}=50\]\[Hz\]You need to login to perform this action.
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