A) 5 W
B) 376.6 W
C) 1883 W
D) 3776 W
Correct Answer: C
Solution :
Wave impedance \[Z=\sqrt{\frac{{{\mu }_{r}}}{{{\varepsilon }_{r}}}}\times \sqrt{\frac{{{\mu }_{0}}}{{{\varepsilon }_{0}}}}\] \[=\sqrt{\frac{50}{2}}\times 376.6=1883\,\Omega \]
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