A) \[2\mu h\]
B) \[\frac{2h}{\mu }\]
C) \[\frac{2h}{\mu -1}\]
D) \[h\,\left( 1+\frac{1}{\mu } \right)\]
Correct Answer: B
Solution :
Image formation by a mirror (either plane or spherical) does not depend on the medium. The image of P will be formed at a distance h below the mirror. If d = depth of liquid in the tank. Apparent depth of \[P={{x}_{1}}=\frac{d-h}{\mu }\] Apparent depth of the image of \[P={{x}_{2}}=\frac{d+h}{\mu }\] \ Apparent distance between P and it's image \[={{x}_{2}}-{{x}_{1}}=\frac{2h}{\mu }\]
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