JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Critical Thinking

  • question_answer
    Specific rotation of sugar solution is 0.01 SI units. 200\[kg{{m}^{-3}}\]of impure sugar solution is taken in a polarimeter tube of length 0.25m and an optical rotation of 0.4rad is observed. The percentage of purity of sugar is the sample is [KCET 2004]

    A)            80%                                          

    B)            89%

    C)            11%                                          

    D)            20%

    Correct Answer: A

    Solution :

               Specific rotation \[(\alpha )=\frac{\theta }{l\,c}\Rightarrow c=\frac{\theta \,}{\alpha l}=\frac{0.4}{0.01\times 0.25}=160\,kg/{{m}^{3}}\] Now percentage purity of sugar solution \[=\frac{160}{200}\times 100=80%\]


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