A) 1.1
B) 1.2
C) 1.3
D) 1.4
Correct Answer: C
Solution :
For A Total number of waves = \[\frac{(1.5)t}{\lambda }\] ....(i) \[\because \] \[\left( \begin{align} & \text{Total number} \\ & \ \ \text{ of waves} \\ \end{align} \right)=\left( \frac{\text{optical path length}}{\text{wavelength}} \right)\] For B and C Total number of waves = \[\frac{{{n}_{B}}\left( \frac{t}{3} \right)}{\lambda }+\frac{(1.6)\left( \frac{2t}{3} \right)}{\lambda }\] ....(ii) Equating (i) and (ii) \[{{n}_{B}}=1.3\]
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