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JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Critical Thinking

  • question_answer
    The maximum number of possible interference maxima for slit-separation equal to twice the wavelength in Young?s double-slit experiment is                                           [AIEEE 2004]

    A)            Infinite                                   

    B)            Five

    C)            Three                                      

    D)            Zero

    Correct Answer: B

    Solution :

               For maxima \[\Delta =d\sin \theta =n\lambda \] Þ \[2\lambda \sin \theta =n\lambda \]Þ \[\sin \theta =\frac{n}{2}\] since value of sin q  can not be greater 1. \ n = 0, 1, 2 Therefore only five maximas can be obtained on both side of the screen.


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