JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Critical Thinking

  • question_answer
    In Young's double slit experiment intensity at a point is (1/4) of the maximum intensity. Angular position of this point is   [IIT-JEE (Screening) 2005]

    A)            sin-1(l/d)                               

    B)            sin-1(l/2d)

    C)            sin-1(l/3d)                             

    D)            sin-1(l/4d)

    Correct Answer: C

    Solution :

               \[I=4{{I}_{0}}\] cos2(f/2)  Þ f = 2p/3 Þ Dx ´ (2p/l) = 2p/3= l/3 sin q = Dx/d  Þ sin q = l/3d


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