A) \[N{{O}_{2}}\]
B) \[S{{O}_{2}}\]
C) \[C{{O}_{2}}\]
D) \[Cl{{O}_{2}}\]
Correct Answer: C
Solution :
Reduction is accompanied by an increase in oxidation number of the reducing agent. C belong to IVA so the max-O.N. is +4. In \[C{{O}_{2}}\] the oxidation number of C is +4, which cannot be further increased. Hence, \[C{{O}_{2}}\]can not act as reducing agent.
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