A) 500 W
B) 700 W
C) 750 W
D) 1000 W
Correct Answer: D
Solution :
\[\frac{{{P}_{t}}}{{{P}_{c}}}=1+\frac{{{m}^{2}}}{2}\] or \[{{P}_{c}}={{P}_{t}}\left[ \frac{2}{2+{{m}^{2}}} \right]\] \ \[{{P}_{c}}=1500\,\left[ \frac{2}{2+1} \right]\] Q m = 100% = 1 = 1000 WYou need to login to perform this action.
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