JEE Main & Advanced Physics Ray Optics Question Bank Critical Thinking

  • question_answer
    In a grease spot photometer light from a lamp with dirty chimney is exactly balanced by a point source distance 10 cm from the grease spot. On clearing the chimney, the point source is moved 2 cm to obtain balance again. The percentage of light absorbed by dirty chimney is nearly 

    A)            56%                                          

    B)            44%

    C)            36%                                          

    D)            64%

    Correct Answer: C

    Solution :

               The actual luminous intensity of the lamp is \[{{I}_{1}}\] whereas the intensity is \[{{I}_{1}}^{\prime }\]in the dirty state. I position, \[\frac{{{I}_{1}}^{\prime }}{{{I}_{2}}}={{\left( \frac{x}{10} \right)}^{2}}\] II position, \[\frac{{{I}_{1}}}{{{I}_{2}}}={{\left( \frac{x}{8} \right)}^{2}}\]  \[\Rightarrow \frac{{{I}_{1}}^{\prime }}{{{I}_{1}}}=0.64\] \[\Rightarrow \ {{I}_{1}}^{\prime }=0.64\,{{I}_{1}}\]. Thus, % of light absorbed = 36%.


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