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JEE Main & Advanced Physics Semiconducting Devices Question Bank Critical Thinking

  • question_answer
    A P-type semiconductor has acceptor levels 57 meV above the valence band. The maximum wavelength of light required to create a hole is (Planck?s constant h = \[6.6\times {{10}^{-34}}\]J-s)                                         [MP PET 1995]

    A) \[57\,{AA}\]

    B) \[57\times {{10}^{-3}}\,{AA}\]

    C) \[217100\,{AA}\]

    D) \[11.61\times {{10}^{-33}}\,{AA}\]

    Correct Answer: C

    Solution :

    \[E=\frac{hc}{\lambda }\]Þ\[\lambda =\frac{hc}{E}\]\[=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{57\times {{10}^{-3}}\times 1.6\times {{10}^{-19}}}\] \[=217100\,{AA}\].


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