A) 2
B) 3
C) 4
D) 5
Correct Answer: B
Solution :
\[{{C}_{2}}{{H}_{3}}C{{l}_{2}}Br\] Three isomers are possible \[C{{H}_{3}}-C\,<-\begin{matrix} Cl \\ Cl \\ Br \\ \end{matrix}\] 1-bromo-1, 1-dichloroethane \[Br-C{{H}_{2}}\,-CH<\begin{matrix} Cl \\ {} \\ Br \\ \end{matrix}\]1-bromo-2, 2-di-chloroethane \[Cl-C{{H}_{2}}\,-CH<\begin{matrix} Br \\ {} \\ Cl \\ \end{matrix}\]1-bromo-1, 2-dichloroethaneYou need to login to perform this action.
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