• # question_answer If $\sin x+\text{cosec}\,x=2,$ then $4\sin A\,\,\sin B\,\,\sin C$ is equal to [UPSEAT 2002] A) 2 B) ${{2}^{n}}$ C) ${{2}^{n-1}}$ D) ${{2}^{n-2}}$

$\sin x+\cos \text{ec}x=2\Rightarrow {{(\sin x-1)}^{2}}=0\Rightarrow \sin x=1$ $\therefore {{\sin }^{n}}x+\text{cose}{{\text{c}}^{n}}x=1+1=2$ .