A) \[\frac{\sqrt{2}}{n}\]
B) \[\sqrt{2}\]
C) 2
D) \[\frac{1}{n}\]
Correct Answer: C
Solution :
Let a, a, ........n times and ? a, ? a, ? a, ? a, ........n times i.e., mean = 0 and S.D.\[=\sqrt{\frac{n{{(a-0)}^{2}}+n{{(-a-0)}^{2}}}{2n}}\] \[2=\sqrt{\frac{n{{a}^{2}}+n{{a}^{2}}}{2n}}=\sqrt{{{a}^{2}}}=\pm a\]. Hence \[|a|\ =2\].You need to login to perform this action.
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