A) 19.97%
B) 20.05%
C) 50%
D) 75%
E) 80.03%
Correct Answer: E
Solution :
Solution contain \[He+C{{H}_{4}}\] Their mol. wt = \[4+16=20\] % wt of \[C{{H}_{4}}\] \[=\frac{\text{wt of }C{{H}_{4}}}{\text{Total wt}}\times 100\]\[=\frac{16}{20}\times 100=80.0%\]You need to login to perform this action.
You will be redirected in
3 sec