A) \[Ag\]
B) \[Hg\]
C) \[Zn\]
D) \[Co\]
Correct Answer: D
Solution :
\[CoC{{l}_{3}}-C{{o}^{+3}}-3{{d}^{6}}4{{s}^{0}}\] 4 unpaired electrons. So it will be coloured.
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