A) \[A{{l}_{2}}{{O}_{3}}\]
B) \[F{{e}_{3}}{{O}_{4}}\]
C) \[Ni{{O}_{2}}\]
D) \[PbO\]
Correct Answer: B
Solution :
\[F{{e}_{3}}{{O}_{4}}\] is a non-stoichiometric compound because in it the ratio of the cations to the anions becomes different from that indicated by the chemical formula.You need to login to perform this action.
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