A) 4
B) 2
C) 6
D) 8
Correct Answer: B
Solution :
\[1458=2\times \underline{3\times 3\times 3}\times \underline{3\times 3\times 3}\] Here 2 is unpaired. So, 1458 must be divided by 2 to make it a perfect cube.2 | 1458 |
3 | 729 |
3 | 243 |
3 | 81 |
3 | 27 |
3 | 9 |
3 | 3 |
1 |
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