A) 14, 21, 35
B) 12, 15, 17
C) 14, 18, 21
D) 21, 28, 32
Correct Answer: A
Solution :
Let the numbers be \[2x,\text{ }3x\] and \[5x\]. So, \[{{(2x)}^{3}}+{{(3x)}^{3}}+{{(5x)}^{3}}=54880\] \[=\text{ }8{{x}^{3}}+\text{ }27{{x}^{3}}+125{{x}^{3}}=54880\] \[\Rightarrow 160{{x}^{3}}=54880\Rightarrow {{x}^{3}}=\frac{54880}{160}=343\] \[\Rightarrow x=\sqrt[3]{343}=7\] So, numbers are 14, 21 and 35You need to login to perform this action.
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